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NCERT Solutions for Class 5 Maths Chapter 3 Page 391.Make big squares and rectangles like this to find the area faster.Ans. For (P) Area= 5 + 2/2 + 7= 5 + 1 + 7 = 13 square cmFor (Q) Area = 7 + 2/2 + 4= 7 + 1 + 4 = 12 square cmFor (R) Area = 6 + 0/2 + 9= 6 + 9 = 15 square cmFor (S) Area == 4 + 0/2 + 6= 4 + 6 = 10 square cmFor (T) Area = 96 + 4/2 + 21= 96 + 2 + 21 = 119 square cm
2.And what about the red triangle?Ans. The area of red triangle is half of the area of rectangle.Hence, area of red triangle = 10 square cm.Ah, in it there are two halves of two different rectangles!
3.Now you find the area of the two rectangles Sadiq is talking about. What is the area of the red triangle? Explain.Ans. Area of two rectangles = Area of red rectangle + area of green rectangle= (3 x 4) + (4 x 2)= 12 + 8 = 20 square cm Hence, area of red triangle together= Half of area of both rectangles together= 1/2 x 20 = 10 square cm.Hence, both triangles have the same area.
4.Yes you are right. And you know what! You can draw many more triangles of area 10 square cm in this rectangle. Try drawing them. Help Sadiq in finding some more such triangles. Draw at least 5 more.Ans.
(b)Draw one straight line in this rectangle to divide it into two equal rectangles.What is the area of each of the smaller rectangles?Ans.A line can be drawn as shown in this figure to divide the given rectangle into two equal rectangles. Similarly, a horizontal line can also be drawn to divide the given rectangle into two equal rectangles.Area of each smaller rectangle=1/2 x Area of bigger rectangle1/2 x 20 = 10 square cm 2b1af7f3a8